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Re: using a function inside a select

Subject: Re: using a function inside a select
From: "David Portabella Clotet"
Date: Wed, 15 Mar 2006 22:53:34 +0100
Hello,

> <d><xsl:value-of select="t1[t2[normalize-space(.)='World']]/t2"/></d>
I see. That's exactly what I was looking for.

Many thanks,
DAvid


On 3/14/06, Henry Zongaro <zongaro@xxxxxxxxxx> wrote:
> Hi, David.
>
> David Portabella Clotet <david.portabella@xxxxxxxxx> wrote on 2006-01-18
> 12:39:21 PM:
> > If I run the compact simple example provided at the end, I get this
> result.
> >
> > <test>
> > <a>Hello</a>
> > <b/>
> > <c>World</c>
> > </test>
> >
> > For 'a' and 'c' it works as expected, but I do not understand the
> > behaviour of 'b'.
> ...
> > xml file:
> > <test>
> >   <t1>
> >     <t2>Hello</t2>
> >     <t2>World</t2>
> >   </t1>
> > </test>
> >
> > stylesheet:
> > <xsl:template match="/test">
> > <test>
> >   <a><xsl:value-of select="t1[t2='World']/t2"/></a>
> >   <b><xsl:value-of select="t1[normalize-space(t2)='World']/t2"/></b>
> >   <c><xsl:value-of select="t1/t2[.='World']"/></c>
> > </test>
> > </xsl:template>
>
>     I don't know whether anybody ever responded to your question, so I
> hope you figured out the problem a long time ago.
>
>     In any event, for the expression, t1[t2='World']/t2 the expression t2
> in the predicate results in a node-set containing the two child element
> nodes of t1.  According to section 3.4 of XPath,[1] if one object in
> relational or equality expression is a node-set and the other is a string,
> the result of the expression is true if and only if there is a node for
> which the expression is true.  The comparison is true for the second t2
> node, so the predicate is true.
>
>     For the expression t1[normalize-space(t2)='World']/t2, the expected
> argument type for normalize-space is "string?".  According to section 3.2
> of XPath,[2] an argument to a function will be converted to the expected
> type - for string, the conversion is performed as if by the string
> function.[3]  Given a node-set as its argument, the string function
> returns the string value of the node that is first in document order.  In
> this case, the argument to normalize-space is effectively the string value
> of the first t2 node, "Hello", so the value of the predicate is false.
>
>     This might be what you're looking for, though I can't be certain,
> since you didn't actually describe what result you needed.
>
> <d><xsl:value-of select="t1[t2[normalize-space(.)='World']]/t2"/></d>
>
>     I hope that helps.
>
> Thanks,
>
> Henry
> [1] http://www.w3.org/TR/xpath#booleans
> [2] http://www.w3.org/TR/xpath#section-Function-Calls
> [3] http://www.w3.org/TR/xpath#function-string
> ------------------------------------------------------------------
> Henry Zongaro      Xalan development
> IBM SWS Toronto Lab   T/L 969-6044;  Phone +1 905 413-6044
> mailto:zongaro@xxxxxxxxxx

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