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Or google >"casus irreducibilis"
Johan E. Mebius
G. A. Edgar wrote:
>In article <1162257513.017058.157220@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
>barr <barr@xxxxxxxxx> wrote:
>
>>It is well known and easy to prove that square roots of complex numbers
>>can be calculated using real square roots. That is you can solve the
>>equation (x + iy)^2 = a + ib for x and y using only real square roots.
>>My question is, is it possible to calculate complex cube roots using
>>only real cube and, if necessay, square roots. I tried, but the
>>equations I got seemed intractible.
>>
>
>The famous "casus irriducibilis" !
>
>Google it.
>
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