| Subject: | Solutions to a cubic? |
|---|---|
| From: | "Gerry" |
| Date: | 29 Sep 2006 09:07:07 -0700 |
| Newsgroups: | sci.math |
Hi can someone help me to verify that the solutions of the cubic ax^3 + (a - 1)x^2 - (b + 1)x + 1 - 2b = 0 can be defined as follows: say b=na+m, and y1=x2-x1,y2=x3-2x2+x1 (x1,x2,x3 are the roots of the cubic) then the following quadratic form in y1,2 (2n+1)a^2+(3m+1)a+1=3y1^2+3y1y2+y2^2 holds. Is it always possible to determin the roots x1,2,3 by solving the quadratic form if we know a,b,n,m? Thanks Gerry |
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