| Subject: | Lipschitz and Locally Lipschitz |
|---|---|
| From: | "Jason Pawloski" |
| Date: | 29 Sep 2006 08:03:58 -0700 |
| Newsgroups: | sci.math |
Let f:(0,1] -> R be defined as f(x) = 1/x, and g:[-1,1] -> R be defined as g(x) = (x)^(1/3). Am I right in saying neither of these functions is Lipschitz, f(x) is locally Lipschitz, and g(x) is not even locally Lipschitz? |
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