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Lipschitz and Locally Lipschitz

Subject: Lipschitz and Locally Lipschitz
From: "Jason Pawloski"
Date: 29 Sep 2006 08:03:58 -0700
Newsgroups: sci.math
Let f:(0,1] -> R be defined as f(x) = 1/x, and g:[-1,1] -> R be defined
as g(x) = (x)^(1/3). Am I right in saying neither of these functions is
Lipschitz, f(x) is locally Lipschitz, and g(x) is not even locally
Lipschitz?


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