Re: exponent law practice

russiandon wrote:

> ( 2^n *  4^n-1 *  8^3n-2 ) / ( 16^2n-1 ) ... Please help me with this
> one. The bases are not the same, so I can't subtract or add exponents.


u should write parenthesis in the above question as following:
2^n*4^(n-1)*8^(3n-2)/(16^(2n-1))
ad ur answer is:
=2^n*2^(2(n-1))*2^(3(3n-2))/(2^(4(2n-1)))
=2^(n+2(n-1)+3(3n-2)-4(2n-1))
=2^(n+2n-2+9n-6-8n+4)
=2^(4n-4)
=2^4(n-1)
=16^(n-1).