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1. For the function f(x) = 1- 1/x^2, find the value c for which the
line x= c divides the area of the region under the graph of f from x=a
to x= b into a 2:1 ratio.
a= 1 and b= 2
How do i do this please?
2. Show that the region enclosed by the graph of the parabola:
y= f(x) = (2/a^2)x - (1/a^3)x^2
for a>0 and the x- axis has an area independent of a. How large is this
area?
Any hints on this one please?
3.What value of m would cause the function g(x) = mx to divide the
region bounded by f(x) = x- x^2 and the x-axis in the first quadrant
into two regions of equal area?
Wouldn't it be m= 1/2x ?
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