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dimension and basis

Subject: dimension and basis
From: "vsgdp"
Date: Tue, 12 Sep 2006 17:39:05 -0700
Newsgroups: sci.math
Show that all symmetric matrices from a vector space, compute its dimension, 
and show a basis in it.

I think I got the first part: I assumed the set of all square matrices 
formed a vector space, then I showed the set of symmetric matrices is a 
subspace.  However, I don't get the 2nd or 3rd.  It seems like it would have 
the same dimension as n x n matrices...I don't see where the degree of 
freedom is lost. 



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