| Subject: | " What about equation : f(m(x ,y) , x ) = f(x ,y) ? " |
|---|---|
| From: | "" |
| Date: | 6 Apr 2006 09:46:58 -0700 |
| Newsgroups: | sci.math |
Voilà ,
f(m(x ,y) ,x ) = f(x ,y) (1)
m and f:R^2 -> R continous for x and y .
In a first step , I examine pairs (f,m) satisfying (1)
such as 1° f(x, y) = constant
2° m(x,y) =y and f(x, y) = f(y, x)
3° f(x ,y) = g(x +(1 -d)*y) ;m(x ,y) =d*x +(1 -d)*y ...
Here is an other exemple:
f(x ,y) = g( 1/x +y^2) ; m(x ,y) = x/(1 - x^3 +x*y^2) .
What must be the link between m(x ,y) and f(x ,y) and
can we build more general solutions ?
Friendly , Alain .
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