Re: euclidean distance question

[quasi]

On 30 Jul 2005 08:39:19 -0700, "asdf" <qjohnny2000@xxxxxxxxx> wrote:

>By distance I mean the if the you are comparing squares (a1,a2,a3,a4)
>to squares ( b1,b2,b3,b4 ) I mean distance = ( a1-b1)^2 + (a2-b2)^2 +
>(a3-b3)^2 + (a4-b4)^2.  I'm think now it follows that from R^2 case
>that this is true..

How is (a1,a2,a3,a4) a square? Looks like a point to me.