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asdf wrote:
> By distance I mean the if the you are comparing squares (a1,a2,a3,a4)
> to squares ( b1,b2,b3,b4 ) I mean distance = ( a1-b1)^2 + (a2-b2)^2 +
> (a3-b3)^2 + (a4-b4)^2. I'm think now it follows that from R^2 case
> that this is true..
I think my last post wasn't the right way for this problem. If we are
in
R^4, lets do things in the plane defined by a and b. If a goes from
the origin to (a1,a2,a3,a4), and b goes from
the origin to (b1,b2,b3,b4), we can say the distance from a to b is d(b
- a),
where da^2 = sum(i=1,4) (ai)^2, etc., giving your formula.
Then d(b/2 - a/2) < d(b - a), as you say.
Van
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