Re: Easy question

[Johann Wiesenbauer]

> The inverse of f=x^n is x=f^(1/n). However, if I plot
> f=x^(1/n) it is
> not a mirror image. I found hint useful but not
> helpful. I still need
> an answer.
> 

Setting e.g. n = 2, then you are saying that for x>=0  the functions y = x^2 
and y = x^(1/2) are not mirror images w.r.t. the line y = x?

Johann