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> > In other words, the proof is rather of functional
> > analytical type:
> >
> > Let f(s) be complex-valued, analytic (i.e.,
> > holomorphic, <=> continuous,)
It should be "holomorphic -> continuous", instead of
"holomorphic <=> [<->] continuous".
> >everywhere except for
> s
> > = 1, f(0 + it) \not= 0 for any positive t, and
> > satisfy
> >
> > |f(Re(s) + it)| = |g(s)||f(1 - Re(s) + it)|,
> >
> > where g(s) is nonzero everywhere. Then f(s) can
> have
> > zeros only at Re(s) = 1/2.
>
>
> "in the critical strip" should be added between
> "Re(s) = 1/2" and "." .
>
>
> >
> > In other words, if you could show a counterexample
> to
> > the theorem above, then my proof will fall on some
> > part.
> >
> > Eldes
> >
> >
> ------------------------------------------------------
>
> > ----
> > This is the way I do math, miss!
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