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> In other words, the proof is rather of functional
> analytical type:
>
> Let f(s) be complex-valued, analytic (i.e.,
> holomorphic, <=> continuous,) everywhere except for s
> = 1, f(0 + it) \not= 0 for any positive t, and
> satisfy
>
> |f(Re(s) + it)| = |g(s)||f(1 - Re(s) + it)|,
>
> where g(s) is nonzero everywhere. Then f(s) can have
> zeros only at Re(s) = 1/2.
"in the critical strip" should be added between "Re(s) = 1/2" and "." .
>
> In other words, if you could show a counterexample to
> the theorem above, then my proof will fall on some
> part.
>
> Eldes
>
> ------------------------------------------------------
> ----
> This is the way I do math, miss!
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