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On 29 Jul 2005 15:36:41 -0700, "Mukhtar Bekkali" <mbekkali@xxxxxxxxx>
wrote:
>Function f=x^n, 0<x<1 and n>1 and f=(1-x)^n are mirror images of each
>other around x=1/2. Can you suggest a function that is a mirror image
>of f=x^n around f=x. For example, in 1x1 square I need to find a
>function that describes the mirror image of f=x^n around diagonal. This
>new function has to be increasing and concave. I am tired and my brain
>has stopped functioning for today. Please solve this problem for me.
>Thx.
Hint: What is the geometric relation between a function and its
inverse?
--Lynn
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