| Subject: | Easy question |
|---|---|
| From: | "Mukhtar Bekkali" |
| Date: | 29 Jul 2005 15:36:41 -0700 |
| Newsgroups: | sci.math |
Function f=x^n, 0<x<1 and n>1 and f=(1-x)^n are mirror images of each other around x=1/2. Can you suggest a function that is a mirror image of f=x^n around f=x. For example, in 1x1 square I need to find a function that describes the mirror image of f=x^n around diagonal. This new function has to be increasing and concave. I am tired and my brain has stopped functioning for today. Please solve this problem for me. Thx. |
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