Re: bXc = b -> b=0 (with regularity but not infinity)

Subject:	Re: bXc = b -> b=0 with regularity but not infinity
From:	"MoeBlee"
Date:	29 Aug 2006 16:41:03 -0700
Newsgroups:	sci.logic

Thanks, Rupert. I'll take it home tonight to think on.

MoeBlee

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Re: bXc = b -> b=0 (with regularity but not infinity), (continued) Re: bXc = b -> b=0 (with regularity but not infinity), Rupert Re: bXc = b -> b=0 (with regularity but not infinity), Rupert Re: bXc = b -> b=0 (with regularity but not infinity), Rupert Re: bXc = b -> b=0 (with regularity but not infinity), Rupert Re: bXc = b -> b=0 (with regularity but not infinity), William Elliot Re: bXc = b -> b=0 (with regularity but not infinity), MoeBlee [] bXc = b -> b=0 (with regularity but not infinity), William Elliot Re: bXc = b -> b=0 (with regularity but not infinity), MoeBlee Re: bXc = b -> b=0 (with regularity but not infinity), MoeBlee Re: bXc = b -> b=0 (with regularity but not infinity), Rupert Re: bXc = b -> b=0 (with regularity but not infinity), MoeBlee <=

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