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Re: Every set x equinumerous with a set y disjoint from x?

Subject: Re: Every set x equinumerous with a set y disjoint from x?
From: "MoeBlee"
Date: 25 Aug 2006 17:04:52 -0700
Newsgroups: sci.logic
Rupert wrote:
> MoeBlee wrote:
> > For ZC (Z set theory with the axiom of choice), I'm pretty sure I see
> > how to prove:
> >
> > AxEy(x equinumerous with y & x/\y = 0)
> >
> > where '/\' stands for binary intersection.
> >
> > But can this be proven without the axiom of choice? If so, how to do
> > it?
> >
>
> Yes, consider x X {x}.

Of course I thought of that. But that doesn't the disjointedness
require the axiom of regularity? I should have been clear to exclude
use of regularity also. So the axioms are

extensionality
separation
pair
union
power
infinity (though, I'd like to exclude it also)

Thanks,

MoeBlee


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