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Re: Simple Calculation of Sunset Time required

Subject: Re: Simple Calculation of Sunset Time required
From: oriel36 <kelleher.gerald@xxxxxxxxx>
Date: Mon, 21 Apr 2008 12:40:17 -0700 (PDT)
Newsgroups: sci.astro, sci.astro.amateur, comp.home.automation

On Apr 21, 7:48 pm, David Weinshenker <daz...@xxxxxxxxxxxxx> wrote:
> oriel36 wrote:
>
> > On Apr 21, 6:18 pm, "TR Oltrogge" <troltro...@xxxxxxxxxxx> wrote:
>
> > >    (2) Elapsed Time
>
> > >        The earth rotates on its own axis approximately every 23 hours 56 
> > > minutes 4 seconds (a sidereal day). So
> > >        even though the observer is fixed in geographic latitude and 
> > > longitude his effective longitude increases
> > >        by 360 degrees every 23h56m4s.
>
> > I still think it is remarkable that there is a large section of people
> > who  have actually  found a way to believe the nonsense of a
> > correlation between  the Earth's rotation through 360 degrees and the
> > value of 23 hours 56 min 04 seconds.If axial rotation is constant,and
> > it has not being isolated as an independent motion to be checked ,the
> > value will almost certainly be 24 hours or,in other words,it will
> > nowhere near 23 hours 56 minutes 04 seconds.
>
> How would you measure the rotation: suppose you landed on this planet
> from outer space, with your own time-measuring devices (that were marked
> in some totally alien units, independent of Earthlings' "hours"), and
> were wondering what the rotation period of the planet was. By what
> observation would you take that measurement? (Observing the apparent
> position of distant stars? Observing the position of sun? Using a
> Foucault pendulum at the pole?)
>
> -dave w- Hide quoted text -
>
> - Show quoted text -

Go ask the guys at the South Pole,they would have no choice but to
work on the 24 hour/360 degree correlation because that is what
Huygens and Harrison worked off  -

"The pendulum will travel in a circle relative to the floor a distance
of (3600)Sinf in 24 hours, ... The latitude at Sonoma State University
is 38 Deg 20’ so the pendulum will subtend an angle of 223Deg  in 24
hours, i.e., it has a period of 38 hours, 45 minutes. At the equator
the latitude is 0o and (360)Sin0 = 0, the pendulum will not appear to
rotate at all but only swing back and forth remaining in the same
plane relative to the floor. At the South Pole the latitude is 90 Deg
and (360)Sin90 = 360  deg so the pendulum will make one complete
revolution in one day. This makes sense because the Earth rotates once
on its axis every 24 hours and the South Pole marks the Earth’s axis
of rotation "

http://www.phys-astro.sonoma.edu/people/students/baker/SouthPoleFoucault.html

No offence to hypothetical 'outer space' reasoning,this is actually a
technical and engineering argument drawn from millenia of astronomical
refinements.If you cannot understand how the Equation of Time
transfers the average 24 hour day to the axial cycle as a constant
then you have a rather large problem that I cannot help you with,the
same goes for everyone else.

With a srtetch I can say it must be some obligation to your peers but
personally the value of 23 hours 56 minutes 04 seconds assigned to
axial rotation through 360 degrees is on par with a flat Earth
notion,that is no exaggeration.














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