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RE: [Haskell-cafe] Restrictions on associated types for classes

Subject: RE: [Haskell-cafe] Restrictions on associated types for classes
From: Simon Peyton-Jones
Date: Thu, 17 Dec 2009 15:31:40 +0000
Hmm.  If you have
   class (Diff (D f)) => Diff f where

then if I have
        f :: Diff f => ...
        f = e
then the constraints available for discharging constraints arising from e are
        Diff f
        Diff (D f)
        Diff (D (D f))
        Diff (D (D (D f)))
        ...

That's a lot of constraints.  

Simon


| -----Original Message-----
| From: [email protected] 
[mailto:[email protected]] On
| Behalf Of Conor McBride
| Sent: 17 December 2009 14:48
| To: Haskell Cafe
| Subject: Re: [Haskell-cafe] Restrictions on associated types for classes
| 
| Hi all
| 
| On 17 Dec 2009, at 14:22, Tom Schrijvers wrote:
| 
| >> class MyClass k where
| >> type AssociatedType k :: *
| >>
| >> Is there a way of requiring AssociatedType be of class Eq, say?
| >
| > Have you tried:
| >
| > {-# LANGUAGE TypeFamilies #-}
| > {-# LANGUAGE FlexibleContexts #-}
| >
| > class Eq (AssociatedType k) => MyClass k where
| >  type AssociatedType k :: *
| 
| I just got very excited about this. I'm supposed to be
| setting a test, but this is far more interesting. I tried
| this
| 
|  > {-# LANGUAGE TypeFamilies, FlexibleContexts, EmptyDataDecls,
| TypeOperators #-}
| 
|  > module DDD where
| 
|  > class (Diff (D f)) => Diff f where
|  >   type D f
|  >   plug :: D f x -> x -> f x
| 
|  > newtype K a x = K a deriving Show
| 
|  > data Void
|  > magic :: Void -> a
|  > magic x = x `seq` error "haha"
| 
|  > instance Diff (K a) where
|  >   type D (K a) = K Void
|  >   plug (K c) x = magic c
| 
|  > newtype I x = I x deriving Show
| 
|  > instance Diff I where
|  >   type D I = K ()
|  >   plug (K ()) x = I x
| 
|  > data (f :+: g) x = L (f x) | R (g x) deriving Show
| 
|  > instance (Diff f, Diff g) => Diff (f :+: g) where
|  >   type D (f :+: g) = D f :+: D g
|  >   plug (L f') x = L (plug f' x)
|  >   plug (R g') x = R (plug g' x)
| 
|  > data (f :*: g) x = f x :& g x deriving Show
| 
|  > instance (Diff f, Diff g) => Diff (f :*: g) where
|  >   type D (f :*: g) = (D f :*: g) :+: (f :*: D g)
|  >   plug (L (f' :& g)) x = plug f' x :& g
|  >   plug (R (f :& g')) x = f :& plug g' x
| 
| But I got this message
| 
| [1 of 1] Compiling DDD              ( DDD.lhs, interpreted )
| 
| DDD.lhs:5:2:
|      Cycle in class declarations (via superclasses):
|        DDD.lhs:(5,2)-(7,28): class (Diff (D f)) => Diff f where {
|                                  type family D f; }
| Failed, modules loaded: none.
| 
| and now I have to go back to setting my class test.
| 
| Sorry for spam
| 
| Conor
| 
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| Haskell-Cafe mailing list
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