Re: [Haskell-cafe] generic sum for an UArr

[Manlio Perillo]

Daniel Fischer ha scritto:
> [...]
> >    genericSumU :: (UA e, Integral e) => UArr e -> Int
> >    genericSumU = foldU add 0
>
> That would have to be foldlU, the type of foldU is
> foldU :: UA a => (a -> a -> a) -> a -> UArr a -> a
>
> while 
> foldlU :: UA a => (b -> a -> b) -> b -> UArr a -> b

Damn...

I was reading the source code of uvector, where
foldU = foldlU

and I totally forgot to check types.


Thanks  Manlio
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