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On 30 Apr, 23:02, arnuld <NoS...@xxxxxxxxxx> wrote:
> .> On Tue, 29 Apr 2008 02:47:18 -0700,Nick Keighleywrote:
> > are all your words the same size?
>
> It depends on the user, what he likes to input at run-time.
in other words, no.
santosh has pointed out some of the design drivers for this.
So decide do you want a fixed size (limits word size and wastes space)
or a variable size (harder to program).
> > If you use the array of pointers you'll have to get the memory
> > for each word from somewhere (eg. malloc())
Note Well
> yes. I came up with this code and as you can see it does not do what I
> want. I want to take every word into the input but it only takes 1st for
> obvious reasons. I am not able to think of the way to take all the words
> of the input:
1. after you read a word you need to skip to the next word.
eg. read until you get a letter
2. you need somewhere to store the words. Either a 2D array or
use malloc().
> #include <stdio.h>
> #include <ctype.h>
>
> enum MAXSIZE { MAXWORD = 100 };
>
> char *getword( char *, int );
>
> int main(void) {
>
> char buffer[MAXWORD];
this only holds one word
char buffer[MAXNUMWORDS][MAXWORD];
OR char* buffer [MAXWORD]
> getword( buffer, MAXWORD );
pass the appropriate argument
<snip>
--
Nick keighley
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