Re: value of the constant expression 1<<(1?1:1) < 0x9999

[Keith Thompson]

Peter Nilsson <airia@xxxxxxxxxxx> writes:
> Keith Thompson wrote:
>> ...
>> I'll assume that types int and unsigned int are 16 bits.
>>
>> 1<<(1?1:1) has the value 2 and is of type int.
>>
>> 0x9999 has the value 39321 and is of type unsigned int.
>>
>> The "usual arithmetic conversions" are applied to the operands
>> of "<". This converts the left operand, 2, from int to unsigned int.
>>
>> So the expression 1<<(1?1:1) < 0x9999 is equivalent to
>> 1U < 39321U,
>
> ITYM:  2U < 39321U

Yes, thanks.

-- 
Keith Thompson (The_Other_Keith) <kst-u@xxxxxxx>
Nokia
"We must do something.  This is something.  Therefore, we must do this."
    -- Antony Jay and Jonathan Lynn, "Yes Minister"