Re: ?: as an lvalue

[Andrey Tarasevich]

Richard wrote:
> ...
> But (c?x:y)=v;
> I dont really know what to say. 

Is there any reason why you believe that the property of "being an 
lvalue" should be necessarily lost in the process of selection from two 
lvalues of the same type?

I mean I'm OK personally with the way it works in C. I just like to know 
what is it exactly in '(c?x:y)=v' that triggers a "I don't really know 
what to say" reaction from some people.

--
Best regards,
Andrey Tarasevich