Re: Strange bit shifting result with gcc - am I missing something obvious?

Bartc <bc@xxxxxxxxxx> wrote:
> 
> On the x86 at least, shifting a 32-bit register left by 32 is anyway a 
> no-operation (the register is unchanged).

On the contrary, different processors in the x86 family behave
differently.  Some only look at the bottom 5 bits of the count (so a
shift count of 32 is interpreted as 0 and 33 as 1) but others look at
the entire value (so a shift count of 32 or greater zeros the register).

-Larry Jones

You're just trying to get RID of me, aren't you? -- Calvin