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#include
int main(void)
{
float bread_price = 0.99;
int bread_count = 3;
float total_price = bread_count * bread_price; // this compiles okay
printf("total price is %.2f \n", total_price);
return 0;
}
I am a newbie, and my understanding is that, roughly speaking, an
expression is usually a mix of operators and operands, and computes a
value. When you use an assigment operator during a declaration and
initialize, you can use an expression on the right hand side of the
assigment state? I do this above, and it compiles okay and seems to
work.
I believe you are only supposed to do this if the variables in the
expression have already had been assigned values. I changed the above
to not have them initialized and it still compiled, and then printed
out 0.00. Maybe the below is not legal C syntax, but I have a smart
compiler?
float bread_price;
int bread_count;
float total_price = bread_count * bread_price; // illegal but compiler
is smart??
Maybe this is not C legal since I never gave 'bread_price' or
'bread_count' a value, but I just have a good compiler that
automatically give them a 0.0 and 0 value respectively. I believe also
I am supposed to use the cast since I am mixing datatypes.
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