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that error usually happens when a call to a find query (in this case a
paginate query) is written wrong. That seems like an app error not
hosting.
On Jan 11, 9:07 am, AD7six <andydawso...@xxxxxxxxx> wrote:
> On Jan 11, 3:37 pm, Ryan Schmidt <google-2...@xxxxxxxxxxxxxx> wrote:
>
> > On Jan 11, 2011, at 07:10, javier0051 wrote:
> > > Code | Context
>
> > > $sql = "SELECT COUNT(*) AS `count` FROM `articles` AS
> > > `Article` LEFT
> > > JOIN `categories` AS `Category` ON (`Article`.`category_id` =
> > > `Category`.`id`) LEFT JOIN `images` AS `Image` ON
> > > (`Image`.`foreign_id` = `Article`.`id` AND `Image`.`thumb` = 1 AND
> > > `Image`.`model` = 'Article') LEFT JOIN `galleries` AS `Gallery` ON
> > > (`Gallery`.`article_id` = `Article`.`id`) WHERE conditions = ('43')
> > > "
> > > $error = "1054: Unknown column 'conditions' in 'where clause'"
>
> > At the risk of stating the obvious, it sounds like there is no column
> > called "conditions".
>
> a missing field named conditions shouts app-code error to me. Given it
> comes from a paginate call, I guess this is in the code:
>
> ->paginate(array('conditions' => array(43)));
>
> which is simply wrong.
>
> javier I'd suggest doing the blog tutorial before continuing - it'll
> answer these sort of problems for you by example.
>
> AD
> ps. there's a spanish google group cakephp-esp
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